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6y^2-16y-70=0
a = 6; b = -16; c = -70;
Δ = b2-4ac
Δ = -162-4·6·(-70)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-44}{2*6}=\frac{-28}{12} =-2+1/3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+44}{2*6}=\frac{60}{12} =5 $
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